This is Part 9 of the “Let’s play EVM Puzzles” series, where I will explain how to solve each puzzle challenge.

EVM Puzzles is a project developed by Franco Victorio (@fvictorio_nan) that a perfect fit if you are in the process of learning how the Ethereum EVM works and you want to apply some of the knowledge you have just acquired.

## EVM Puzzle 9

```
00 36 CALLDATASIZE
01 6003 PUSH1 03
03 10 LT
04 6009 PUSH1 09
06 57 JUMPI
07 FD REVERT
08 FD REVERT
09 5B JUMPDEST
0A 34 CALLVALUE
0B 36 CALLDATASIZE
0C 02 MUL
0D 6008 PUSH1 08
0F 14 EQ
10 6014 PUSH1 14
12 57 JUMPI
13 FD REVERT
14 5B JUMPDEST
15 00 STOP
```

This puzzle is much simpler compared to the previous one. It's just a question to solve some math equations.

Let's see what new opcodes have been introduced:

- LT: pop 2 values from the stack and push the result of
`value0 < value1`

to the stack. If the result is true, it pushes`1`

otherwise`0`

. - CALLVALUE: push to the stack the value of the current call in
`wei`

## Block 1: check calldata size

```
00 36 CALLDATASIZE
01 6003 PUSH1 03
03 10 LT
04 6009 PUSH1 09
06 57 JUMPI
07 FD REVERT
08 FD REVERT
09 5B JUMPDEST
```

This block check if the size in byte of the `calldata`

is less than 3. If so, it does not follow the `JUMPI`

jump and revert. That's our first requirement. Our `calldatasize`

must be greater or equal of `3`

.

## Block 2: Check the calldata size and value

```
09 5B JUMPDEST
0A 34 CALLVALUE
0B 36 CALLDATASIZE
0C 02 MUL
0D 6008 PUSH1 08
0F 14 EQ
10 6014 PUSH1 14
12 57 JUMPI
13 FD REVERT
14 5B JUMPDEST
15 00 STOP
```

The next block of code instead push to the stack the multiplication of `calldata`

size in bytes and calldata value in `wei`

.

If the result is not equal to 8 it will not follow the `JUMPI`

jump and revert. This means that the second requirement is that `MUL(calldata_size, calldata_value)`

must be equal to 8.

## Solution

There are many possible solutions, we just need to follow these requirements:

- `CALLDATASIZE >= 3
`CALLVALUE * CALLDATASIZE === 8`

For example, `0xFFFFFFFFFFFFFFFF`

as calldata and `1 wei`

as value will solve the challenge, but also `0xFFFFFFFF`

and `2 wei`

will do it!

Here's the link to the solution of Puzzle 9 on EVM Codes website to simulate it.